Find the number of distinct triangles with the measurements a=1 b=2 and a=31 degrees

No triangle possible.

Step-by-step explanation:

Let in triangle ABC,

BC = a = 1 unit,

AC = b = 2 unit,

m∠A = 31°,

By the law of sine,

⇒ m∠B= undefined

( ∵ the value of sin Ф lies from 0 to 1 where Ф is an angle )

An angle of a triangle can not be undefined.

∴ Triangle ABC is not possible,

That is, there is no possible triangle with the given measures.

what are the options? ?

step-by-step explanation:

37/3

step-by-step explanation:

step 1: simplify both sides of the equation.

7x+8(x+

1

4

)=3(6x−9)−8

7x+(8)(x)+(8)(

1

4

)=(3)(6x)+(3)(−9)+−8(distribute)

7x+8x+2=18x+−27+−8

(7x+8x)+(2)=(18x)+(−27+−8)(combine like terms)

15x+2=18x+−35

15x+2=18x−35

tep 2: subtract 18x from both sides.

15x+2−18x=18x−35−18x

−3x+2=−35

step 3: subtract 2 from both sides.

−3x+2−2=−35−2

−3x=−37

step 4: divide both sides by -3.

−3x

−3

=

−37

−3

x=

37

3