Shaneya purchased a membership to play basketball at her local gym. The membership costs $75 for the year, plus she pays $3 to rent equipment each time she goes. If Shaneya doesn't want to spend any more than $150 on basketball for the year, what is the maximum amount of times can she go to the gym to play?

25

Step-by-step explanation:

Step one:

given data

We are told that Shaneya purchased a membership to play basketball at her local gym.

Costs =  $75 for the year,

Rent =  $3 for equipment each time she goes

Given that she has $150 to spend,

Step two:

Firstly, let us model the situation

let the total amount she has to spend be y

and the number of time she goes to the gym be x

y= 75+3x

for y= 150, let us find the value of x

150= 75+3x

150-75= 3x

75= 3x

divide both sides by 3

x= 75/3

x=25 times

The maximum amount of times is 25

the answer is 9.8975

explanation:

when you multiply the "39.59" with the 25% it reduces it and shows its final discounted price. hope this !

step-by-step explanation:

hope it you

step-by-step explanation:

sin(7pi/6 - pi/3)  

= sin(7pi/6 - 2pi/6)  

= sin(5pi/6)  

= sin(pi - pi/6)  

= sin(pi/6)  

= 1/2  

sin 7pi/6 - sin pi/3  

= sin (pi + pi/6) - sin pi/3  

= -sin pi/6 - sin pi/3  

= -1/2 - sqrt(3)/2  

= -(1+sqrt(3))2