Julio tested the point (4, –2) to see whether it is a solution to this system of equations. –3x – 2y = –8,
y = 2x – 5

His work is shown below.

Negative 3 (4) minus 2 (negative 2) = negative 8. Negative 12 + 4 = negative 8. Negative 8 = negative 8. Therefore, (4, negative 2) is a solution to the system.

Did Julio verify the solution?
a. No. He substituted 4 and –2 for the wrong variables.
b. No. He did not check the point in the second equation.
c. No. He simplified the equation incorrectly.
d. Yes. He verified that (4, –2) is a solution to the system of equations.

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3

make sure you have version 2.50

try looking in the very back of the book : )

step-by-step explanation:

you can download it here

a28=58

step-by-step explanation:

a1=a1+(n-1)d

a28= 4+ (28-1)2

a28=4+(27)(2)

a28=4+54

a28=58