Please help me with this

9514 1404 393

  98°

Step-by-step explanation:

Inscribed angle FGH is half the measure of the intercepted arc FH. The measure of arc FH is identical to the measure of central angle FIH. So, angle FIH has twice the measure of inscribed angle FGH:

  ∠I = 2×∠G = 2×49°

  ∠I = 98°

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2

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step-by-step explanation: