There are three consecutive integers, such that six times the first, minus two times the second, equals the third integer plus five. What is the first integer described? Will give Brainliest

3

Step-by-step explanation:

Given that:

Integers : x, x + 1, x + 2

6x - 2(x + 1) = (x+2) + 5

6x - 2x - 2 = x + 2 + 5

4x - 2 = x + 7

4x - x = 7 + 2

3x = 9

x = 9/3

x = 3

First integer = x = 3

2nd integer = x + 1 = 3+1 = 4

3rd Integer = x + 1 + 1 = 3 + 2 = 5

i think that you should ask google for the answer to that problem because if we don't know it google does