Please answer this. Thankyou!

The y-intercept is b=y1−m⋅x1
b
=
y
1
−
m
⋅
x
1
.
b=1−(3)⋅(3)=−8
b
=
1
−
(
3
)
⋅
(
3
)
=
−
8
.
Finally, the equation of the line can be written in the form y=mx+b
y
=
m
x
+
b
.
y=3x−8
y
=
3
x
−
8
.

The slope of the line is m=3
m
=
3
.
The equation of the line in the slope-intercept form is y=3x−8
y
=
3
x
−
8
.
The equation of the line in the point-slope form is y−1=3(x−3)
y
−
1
=
3
(
x
−
3
)
.
The general equation of the line is 3x−y−8=0
3
x
−
y
−
8
=
0
.

Where’s the stuff st? ? lol sorry