The perimeter of a rectangle is forty inches. The length is two inches more than three times the width. Find the dimensions of
the rectangle.

Let Width (inches)  = X

Let Length (inches) = 3x + 2

40 = (x) + (3x + 2) + (x) + (3x +2)

40 = 8x + 4

-4           -4

36 = 8x

/8     /8

4.5 = x (width)

Length = 3x + 2

length = 3(4.5) + 2

length = 13.5 + 2

length = 15.5 inches

CHECK

40 = 15.5 + 4.5 + 15.5 + 4.5

40 = 20 + 20

40 = 40

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length

they can both be solutions depends on the equation

step-by-step explanation:

what is the equation? ?