whats the equation for the perpendicular bisector of the line segment whose endpoints are (-5,3) and (3,7)?

The equation of perpendicular bisector of the line segment passing through  (-5,3) and (3,7) is:

Step-by-step explanation:

Given points are:

(-5,3) and (3,7)

The perpendicular bisector of line segment formed by given points will pass through the mid-point of the line segment.

First of all we have to find the slope and mid-point of given line

Here

(x1,y1) = (-5,3)

(x2,y2) = (3,7)

The slope will be:

The mid-point will be:

Let m1 be the slope of the perpendicular bisector

Then using, "Product of slopes of perpendicular lines is -1"

We have to find the equation of a line with slope -2 and passing through (-1,5)

The slope-intercept form is given by:

Putting the point (-1,5) in the equation

The final equation is:

Hence,

The equation of perpendicular bisector of the line segment passing through  (-5,3) and (3,7) is:

use formula for the circle a=3.14

step-by-step explanation: