I ALREADY ASKED THIS QUESTION BUT SINCE NO ONE ACTUALLY HELPED ME IM ASKING AGAIN BC I REALLY NEEDA TURN IT IN SO PLEASEEE HELP!! A 20 foot ladder is placed against a wall at a 75 degree angle with the ground. The wall is perpendicular to the ground.

PART A: How high on the wall, in feet, will the ladder reach? Round your answer to the nearest tenth. Show your work.

PART B: What is the distance, in feet, from the wall to the base of the ladder? Show your work.

A. 19.3ft     B. 5.2ft

Step-by-step explanation:

So the ladder leaning against the wall forms a triangle. The hypotenuse of

triangle is the ladder (20) and the angle given between ladder an ground is 75 degrees. Use trig to find the height of the wall which is the leg of the triangle.

Sine of Angle is opposite side/hypotenuse

Cosine of Angle is adjacent side/hypotenuse

so     Sine of 75 degrees  =  Wall height/20

Wall height = 20 times Sine of 75 degrees

Sine of 75 degrees = .9659

20 times (.9659) = 19.3ft

So now use Cosine to find the other leg of the triangle (the distance between the bottom of ladder to the wall)

Cosine of 75 degrees  = Distance wall to base of ladder / 20

Cosine of 75 degrees = .2588

20 times (.2588) = 5.2ft

solution:

the given function is ,

      =

the three roots of this quadratic function is , 0 ,8 and 10.all the roots are real and rational.

if a quadratic equation is of the form ,

sum of the roots = a + b +c= 0+8+10=18=  

product of roots taken two at a time = a b + b c+ c a = 0+80+0=80 =  

product of roots = a b c = 0=  

there are 11 doors in a hall starting from 0 to 11.the entry in the hall is permitted through gate number 0 and exit is allowed through only gate number 8 and 10.so, three roots(0,8,10) of quadratic function is given by entry and exit route of this hall.

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