Use the quotient rule to find the derrivatives of 3/x^2

f'(x) = -6/x³

Step-by-step explanation:

We are given;

f(x) = 3/x²

Using quotient rule, we can write as;

f(x) = g(x)/h(x)

To find the derivative, from quotient rule, we can write;

f'(x) = [(h(x)*g'(x)) - (g(x)*h'(x))]/(h(x))²

g'(x) = 0

h'(x) = 2x

Thus;

f'(x) = [(x²*0) - (3*2x)]/(x²)²

f'(x) = -6x/x⁴ = -6/x³

f'(x) = -6/x³

ye

step-by-step explanation:

10a^3+277a^2-132a-792

step-by-step explanation:

(2a+11)(5a-12)(foil)

=10a^2-24a+55a-132 =10a^2+31a-132

(10a^2+31a-132)(a+6)

=10a^3+60a^2+31a^2+186a^2-132a-792 =10a^3+277a^2-132a-792

i hope this is what you are looking for : )