Find the height of an equilateral triangle with side length 8.

U need to just do

4

Step-by-step explanation:

The segment from a vertex to the side opposite is a perpendicular bisector.

The equilateral Δ is divided into 2 right triangles with legs 8 and 4

let height be h, then using Pythagoras' identity

h² = 4² + 8² = 16 + 64 = 80 ( take the square root of both sides )

h = = 4 ← exact value

lol we need to see what the question is asking about

step-by-step explanation:

(5x-1)^2= (5x)^2-2(5x)×1+(1)^2=25x^2-10x+1