Now let's assume that you have a newer toilet that uses 6 L per flush, but you are considering upgrading to a dual-flush toilet. If you flush the toilet four times per day, but three of those times you could use the 3 L flush, how many liters of water would you save in 1 year

3,285 Liters

Step-by-step explanation:

In the actual case, all your flushes consume 6 L of water.

You flush 4 times per day, then you consume 4 times 6 L per day, this is:

4*6L = 24 L per day.

And in one year there are 365 days, then in one year you consume:

365*24 L = 8,760 L

Now, if you upgrade the toilet, now per day you use:

one time 6 L and 3 times 3 L

Then in day, you use:

1*6 L + 3*3 L = 6L + 9L = 15L

And in the complete year, you will use 365 times that, which is:

365*15 L = 5,475 L

The amount of water that you would save is equal to the difference between the amount that you use in one year with no upgrade (8,760 L) and the amount that you would use in a year if you upgraded your toilet ( 5,475 L)

The difference is:

D = 8,760 L - 5,475 L = 3,285 L

This means that, in this situation, you would save 3,285 liters of water per year if you upgrade your toilet.

based on context clues you gave i'm assuming the answer would be c.

given hc ∥ gd.¯¯¯¯¯¯which statement is true

step-by-step explanation:

∠cbe and ∠deb are same-side interior angles