Consider the following frequency table representing the scores on a test. Scores on a Test

Class Frequency
40–43 7
44–47 7
48–51 7
52–55 8
56–59 4

Required:
a. Determine the lower class boundary for the fifth class.
b. Determine the upper class boundary for the second class.
c. Determine the class width of each class.
d. Determine the number of scores between 39.5 and 55.5

(a)56

(b)47

(c)3

(d)29

Step-by-step explanation:

From the given frequency

(a) Fifth class is 56-59.

    The lower class boundary for the fifth class is 56.

(b) Second class is 44-47.

    The upper-class boundary for the second class is 47.

(c) Class width = 47-44 = 3, 47-44 = 3.

(d) Number of scores between 39.5 and 55.5 is

    =7 + 7+ 7 + 8 =29

answer: i guess 105 degrees?

step-by-step explanation:

in the math equation 8 x 7 = 56, the 8 and the 7 are both factors of 56, since in this lesson we will use square tiles to figure out the factors of a whole find as many different arrays as you can, but follow one important rule: all the rows must have the i can make two rows of nine, so 2 and 9 are both factors of 18.

step-by-step explanation: