What is step 4? PLS HELP, will mark branliest!! Step 1 KL is parallel to the y-axis, and JL is parallel to the x-axis.
Step 2 AJKL was rotated 90° clockwise to create AJ'KL's Point K did not change position, so it remains point K. Therefore, AJKL & AJ'KL
Step 3 KL' is perpendicular to the y-axis, and J'L' is perpendicular to the x-axis.
Step 4 ?
Step 5 J'K lies on line g and has a slope of
Step 6 The product of the slopes of JK and J'K is -1; therefore, lines fand g are perpendicular
J'K lies on line f and has a slope of 3.
JK lies on line f and has a slope of 3
KL Hesenline and has a slepe-of-3.
O-KL tes entine fand has a stope of 3