Shannon and Bob are members of a cross-country team. Bob runs at a rate of 8 kilometers per hour and Shannon runs at a rate of 10 kilometers per hour. If the distance around the team's practice course is 1.7 kilometers, how much longer does it take Bob to complete one trip around the course than Shannon, to the nearest tenth of a minute?

2.6 minutes

Step-by-step explanation:

Speed of Bob = 8 km/hr

Speed of Shannon = 10 km/hr

Distance of practice course = 1.7 km

As time = (distance)/(speed), so

Time taken by Bob to cover the distance, t1 = 1.7/8=0.2125 hours

Time taken by Shannon to cover the distance, t2 = 1.7/10= 0.17 hours

As t1 > t2, so, Bob takes more time than Shannon to complete the course.

t1-t2= 0.2125-0.17 = 0.0425 hours = 0.0425 x 60 minutes= 2.55 minutes.

On rounding up to tenth digit, t1-t2 = 2.6 minutes.

Hence, It takes 2.6 minutes more time for Bob to complete one trip around the course than Shannon

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c

step-by-step explanation:

x² + 3x + 7 = 0       [ax² + bx + c]

a = 1

b = 3

c = 7

quadratic formula:

    (+/- is this ±)

plug in the numbers into the variables

your answer is a