How do you find the domain and range of f(x)=8x^2-5x 2?

The domain of f(x) = 8x^2 - 5x + 2 is all real numbers.
For the range, f(x) = 8x^2 - 5x + 2 written in vertex form is f(x) = 8(x^2 - 5/8x + 1/4) = 8(x^2 - 5/8 + 25/256 + 1/4 - 25/256) = 8(x - 5/16)^2 + 8(39/256) = 8(x - 5/16)^2 + 39/32
The range is all real numbers greater than or equal to 39/32

40%=2/550=1/230=3/1056=14/25

First subtract 10 from both side
y^2+6y-16=0
(y+8)(y-2)=0
-8 and 2