James is playing a dice game. He is rolling two 6-sided dice. To win, the two dice must sum to a number greater than 7. What is the probability that he will win?

9/20

Step-by-step explanation:

4+4=8, 4+5=9, 4+6=10, 5+5=10, 5+6=11, and 6+6=12 are the nine possible roll combinations that have a sum greater than 7 out of the possible 20 different combinations. This makes the probability of rolling a sum greater than 7 a nine in twenty chance.

you didn't post any answer choices, so its not 100% clear what your teacher is looking for

however, log(15/7) is equivalent to log(15) - log(7)

i'm using the rule log(x/y) = log(x) - log(y)