10. (02.03) Find the solution of 3 to the square root of x+6=-12 , and determine if it is an extraneous solution. (1 point)
x= -3; extraneous
x = -3; not extraneous
x= 10; extraneous
x= 10; not extraneous

x= 10; extraneous

Step-by-step explanation:

Given the expression:

3√x+6 = -12

We are to find the value of x

Divide both sides by 3

3√x+6/3 = -12/3

√x+6 = -4

Square both sides

(√x+6)² = (-4)²

x + 6 = 16

x = 16-6

x = 10

Hence the solution is x =10 and it is extraneous solution

4

step-by-step explanation:

6 (donuts) divided by 3 is 2.

so 2/3 means 2 times 2, which is 4/6.

you get two and your friend gets four.

i believe the answers 600m