A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation.
Using this equation, find out the time at which the rocket will reach its
max, to the nearest 100th of a second.
y= -16x2 + 238x + 81

first one is a: renaming a fraction. second one is c: de-c

step-by-step explanation:

my explanation is that these were the answers on edg : )

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