Examine these points on line u and line v. Line u: (9, –8), (5, 4) Line v: (4, 2), (7, –7) How many points of intersection are there between line u and line v?

The line u and line v have no point of intersection because they are parallel lines

Step-by-step explanation:

The slope of a straight line is given as follows;

The slope of line u is (4 - (-8))/(5 - 9) = -3

The equation for line u is y - 4 = -3*(x - 5)

y = -3·x + 15 + 4 = 19 - 3·x

The slope for line v is (-7 - 2)/(7 - 4) = -3

The equation for the line v is y - 2 = -3*(x - 4)

∴ y = -3x + 12 + 2 = -3x + 14

y = 14 - 3·x

Therefore. line u and line v have the same slope and are therefore parallel and they do not intersect

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.