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Evaluate b3 + 6 if b = 2.

b3 +6 (plug in the given value for b and solve)

(2)3 +6 (multiply)

6 + 6 (add)

12 (your answer)

Step-by-step explanation:

I hope this helped :)

f(x) = x^3 -2x^2 -3x

x( x^2 -2x-3)

x( x^2 +x -3x -3)

x( x(x+1) -3(x+1))

x( x-3)( x+1)

so zeroes are 0, 3,-1

its (2) option

answer:

what is your question that you ask

step-by-step explanation: