The question is in the photo

no solutions

Step-by-step explanation:

3(x+5)-3 = 2(3x + 1) - 3x

open the parenthesis

3x + 15 - 3 = 6x + 3 - 3x

add 3x to both sides of the equation

3x + 3x + 15 - 3 = 6x + 3 - 3x + 3x

combine like terms

6x + 15 - 3 = 6x + 3

add 3 to both sides of the equation

6x + 15 - 3 + 3 = 6x + 3 + 3

6x + 15 = 6x + 6

subtract 6 from both sides of the equation

6x + 15 - 6 = 6x + 6 - 6

6x + 15 - 6 = 6x

6x + 9 = 6x

subtract 6x from both sides of the equation

9 = 0

since 9 does not equal 0, the answer is no solutions

a box 3 3/4 feet long or 4+ feet.

step-by-step explanation:

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.