Find the missing side lengths . Leave your answers as radicals in simplest form. Does anybody knows how to do it cause I don’t so can y’all plz help me

Step-by-step explanation:

Question 9:

Hypotenuse = 7

Leg = Hypotenuse / √2 = 7/√2 = 7√2 / 2.

Therefore x = y = 7√2 / 2.

Question 10:

Leg = 10

Since x is also a Leg, x = 10.

Hypotenuse = Leg * √2 = 10√2. => y = 10√2.

Question 11:

Leg = 7

Since x is also a Leg, x = 7.

Hypotenuse = Leg * √2 = 7√2, => y = 7√2.

infinitely many solutions

step-by-step explanation:

we have been given the equation;

2(2x + 3) = -4 + 2(2x + 5)

we need to determine the value of x.

2(2x + 3), we expand this expression to obtain 4x + 6

similarly 2(2x + 5) will become 4x + 10

now we have;

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 10 - 4

4x + 6 = 4x + 6

the expression on the left hand side is identical to the one on the right hand side. therefore, we are looking at just a single straight line whose equation is;

y = 4x + 6

consequently, we shall have infinitely many solutions

in simplified version   it would be x ≤-4

step-by-step explanation:

multiply each term in x ≤-4 by -1