The lines AB and CB intersect at B (a) Find the co-ordinates of the midpoint of AB
(b) Find the equation of the line CB

Step-by-step explanation:

Soln

given,

from the figure

coordinate of B is (5,3),

A(7,0) and C(0,4)

A. solution

let, M(x,y) be the mid point of AB

A(7,0) = (x1,y1)

B(5,3) = (x2,y2)

we know

x = (x2+x1)/2

or, x = (5+7)/2

or, x = 12/2

or, x = 6

and for y

y = (y2+y1)/2

or, y = (3+0)/2

or, y = 3/2

therefore M(x,y) = (6,3/2)

B. solution

let,

C(0,4) = (x1,y1)

B(5,3) = (x2,y2)

equation of line is ;

(y - y1)/(x - x1) = (y2 - y1)/(x2 - x1)

or, (y - 4)/(x -0) = (3 - 4)/(5 - 0)

or, (y - 4)/(x - 0) = -1 / 5

by cross multiply

or, 5×(y - 4) = -1×(x)

or, 5y - 20 = -x

or, x + 5y = 20 is the required equation.

9) i can't see the angle so whatever it is just do this: cos(angle) x hypotenuse and then use that answer and they hypotenuse and plug it into this: (answer you just got)^2 + b^2 = (hypotenuse)^2. the first answer will be the answer of the adjacent side and the second answer after this equation will be the opposite side.

10) y = 14 x = √147 or 12.12435565

11) x = 4.8

12) x = 4.2

13) x = 9.3

14) pq: 13.2

qr : 17.6

angle p: 53º

15) angle c: 54.3º

angle a: 35.7º

16) h = 21040

v = 1841

step-by-step explanation:

10) 7/sin(30) = 14 = y

7^2 + b^2 = 14^2

49 + b^2 = 196

b^2 = 196 - 49

√b^2 = √147

x = √147

11) cos(70) x 14 = 4.788282007

x = 4.8

12) tan(25) x 9 = 4.196768923

x = 4.2

13) sin(31) x 18 = 9.270685348

x = 9.3

14) pq: sin(37) x 22 = 13.23993051

pq: 13.2

qr: cos(37) x 22 = 17.56998122

qr : 17.6

angle p: 180 - (37 + 90) = 53º

15) cos-1(7/12) = 54.31466529

angle c: 54.3º

angle a: 180 - (90 + 54.31466529) = 35.68533471

angle a: 35.7º

16) 4 x 5280 = 21120

cos(5) x 21120

h = 21039.63202

h = 21040

sin(5) x 21120

v = 1840.729287

v = 1841

exa:

)

3+11

14

step-by-step explanation:

from this example, we can see that subtracting with integers is the same as adding the opposite. we can solve using a number line or by using the saying "keep, change, change" to us solve. it is important to remember that we can subtract a negative and end up with a larger number than we started with.