The graph below shows the height of a projectile t seconds after it is launched. If acceleration due to gravity is –16 ft/s2, which equation models the height of the projectile correctly? h(t) = at2 + vt + h0

h(t) = –16t2 + 42t + 5
h(t) = –16t2 + 5
h(t) = –16t2 + 32
h(t) = –16t2 + 32t + 5

Step-by-step explanation:

The graph below shows the height of a projectile t seconds after it is launched. If acceleration due to gravity is –16 ft/s2, which equation models the height of the projectile correctly?

h(t) = at2 + vt + h0

h(t) = –16t2 + 42t + 5

h(t) = –16t2 + 5

h(t) = –16t2 + 32

h(t) = –16t2 + 32t + 5

x -

median = 1.25

range = 12-14.5

interquartile = q12-q14.5

y -

median = 1

range = 15-17

interquartile = q15-q17

you are uyytr tyy

step-by-step explanation: