Determine whether the function f(x) = -9.5 + 6 + x² is even, odd or neither.

The function f(x) = -9.5 + 6 + x² is neither odd or even.

Step-by-step explanation:

We know that a function is termed as 'even' when

f(-x) = f(x) for all x

We know that a function is termed as 'odd' when

f(-x) = -f(x) for all x

Given the function

f(x) = -9.5x⁵ + 6 + x²

substitute x with -x

f(-x) = -9.5(-x)⁵ + 6 + (-x)²

as (-x)⁵ = -x⁵, so

f(-x) = -(-9.5x)⁵ + 6 + (-x)²

Apply exponent rule: (-a)ⁿ = aⁿ, if n is even

f(-x) = -(-9.5x)⁵ + 6 + x²

Apply rule: -(-a) = a

f(-x) = 9x⁵ + 6 + x²

As

f(-x) ≠ f(x) ≠ -f(x)

Therefore, the function f(x) = -9.5 + 6 + x² is neither odd or even.

i got 10.28 but that rounds up to 10.3

answer: 800

step-by-step explanation: