prove that the equation (a^(2)-5ab)-(7-3ab)+(2ab-a^(2)) is equivilent to -7 please show it step by step! Tysm!

Step-by-step explanation:

(a^2 - 5ab) - (7 - 3ab) + (2ab - a^2) = -7

a^2 - 5ab -7 +3ab + 2ab -a^2 = -7 [combine like terms]

a^2 - a^2 = 0

-5ab + 3ab + 2ab = 0

-7 = -7

the correct answer is c

t= 1/3.

hope this .

step-by-step explanation: