A rectangular soccer field may have a width between 50 and 100 yards and a length between 100 and 130 yards. One particular soccer field has a perimeter of 320 yards. Its
length measures 40 yards more than its width. What are the dimensions of this field?

The length is___yards.

The width isyards.

9514 1404 393

Step-by-step explanation:

Let w represent the width of the field. Then the length is (w+40), and the perimeter is ...

  P = 2(L +W)

  320 = 2((w+40) +w) . . . . fill in values

  160 = 2W +40 . . . . . . . . . divide by 2, collect terms

  80 = w +20 . . . . . . . . . . .  divide by 2

  60 = w . . . . . . . . subtract 20

  w+40 = 100

The length is 100 yards; the width is 60 yards.

d

step-by-step explanation:

d

{x = -1/2 ,   y = -1

step-by-step explanation:

solve the following system:

{2 x + y = -2

{10 x - 3 y = -2

in the first equation, look to solve for y:

{2 x + y = -2

{10 x - 3 y = -2

subtract 2 x from both sides:

{y = -2 x - 2

{10 x - 3 y = -2

substitute y = -2 x - 2 into the second equation:

{y = -2 x - 2

{10 x - 3 (-2 x - 2) = -2

10 x - 3 (-2 x - 2) = (6 x + 6) + 10 x = 16 x + 6:

{y = -2 x - 2

{16 x + 6 = -2

in the second equation, look to solve for x:

{y = -2 x - 2

{16 x + 6 = -2

subtract 6 from both sides:

{y = -2 x - 2

{16 x = -8

divide both sides by 16:

{y = -2 x - 2

{x = -1/2

substitute x = -1/2 into the first equation:

{y = -1

{x = -1/2

collect results in alphabetical order:

answer:   {x = -1/2 ,   y = -1