A) If a and B are the roots of the equation 3.x2 - 6x + 5 = 0, find the equation whose roots are a + B and
2÷a+B

Step-by-step explanation:

α and β are roots of 3x² - 6x + 5 = 0.

By Vieta's Formula,

we have αβ = 5/3 and α + β = 2.

To find the equation with roots α + β and 2/(α + β),

we find the Sum and Product of these roots.

=> Sum = (α + β) + 2/(α + β) = (2) + 2/(2) = 3.

=> Product = (α + β) * 2/(α + β) = 2.

Hence we have Ax² + Bx + C,

where -B/A = 3 and C/A = 2.

Simplest form is A = 1, B = -3, and C = 2.

Hence the equation with roots

α + β and 2/(α + β) is x² - 3x + 2.

all teachers

step-by-step explanation:

(n^3 - n)

= n(n-1)(n+1)

since it is divisible by 3 and 2 ,because it is a multiple 3 consecutive number

if, n-1 is odd then n+1 is also odd, then it is a multiple of 9

but if, n-1 is even then n+1 is also even, then it is a multiple of 4

so, largest multiple = max(9*2, 4*3) = max(18, 12) = 18