PLEASE HELP I NEED AND ANSWER Flying against the wind, an airplane travels 5040 kilometers in 6 hours. Flying with the wind, the same plane travels 6000 kilometers in 5 hours. What is the rate of the plane in still air and what is the rate of the wind?

The rate of plane in still air is 1020 kilometers per hour and rate of wind is 180 kilometers per hour.

Step-by-step explanation:

Given that:

An airplane travels 5040 kilometers in 6 hours against the wind

An airplane travels 6000 kilometers in 5 hours with the wind

Let,

x be the speed of plane in still air

y be the rate of wind

Combined speed against the wind = x - y

Combined speed with the wind = x+y

Speed =

x-y=

x - y = 840    Eqn 1

x + y =    Eqn 2

Adding Eqn 1 and 2

x+y+x-y=1200+840

2x=2040

Dividing both sides by 2

Putting x=1020 in Eqn 2

1020+y=1200

y=1200-1020

y=180

Hence,

The rate of plane in still air is 1020 kilometers per hour and rate of wind is 180 kilometers per hour.

if you are saying purchasing 3 social media ads and one newspaper ad counts as one purchase then there are:

6 purchases

if you are asking how many of each then:

18 social media ads

6 newspaper ads

the correct answer is x/3+10≥32

hope this !