What is the equation of the line that is parallel to the linear graph of y = 2x - 1 and passes through the point (-1, 1)? A. O y=-3x+
B. O y = 2x - 3
CO y = 2x
DO y = 2x + 3

The equation of the line that is parallel to the linear graph of y = 2x - 1 and passes through the point (-1, 1) will be:

Hence, option D is true.

Step-by-step explanation:

We know that linear function can be represented using the slope-intercept formula

y = mx+b

where m is the slope and b is the y-intercept

Given the equation

y = 2x - 1

comparing with the slope-intercept form y = mx+b

Hence, the slope of the line y = 2x - 1 is: m = 2

We know that the parallel lines have the same slopes.

Thus, the slope of the equation of the line that is parallel to the linear graph of y = 2x - 1 will also be: 2

Using the point-slope form of the line equation

where m is the slope of the line and (x₁, y₁) is the point

substituting the values of the slope = 2 and the point (-1, 1)

Add 1 to both sides

Simplify

Therefore, the equation of the line that is parallel to the linear graph of y = 2x - 1 and passes through the point (-1, 1) will be:

Hence, option D is true.

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step-by-step explanation: