A company produces two different sizes of soup cans. The volume of the cans varies jointly with the square of the can's radius and the height. The smaller can has a height of 5 inches, a squared radius of 4 inches, and a volume of about 62.8 cubic inches. What is the volume of the taller can, which has a height of 9 inches and a squared radius of 4 inches? Round to the nearest tenth, as needed. A. V=113.0
B. V=36.0
C. V=3.1
D. 91.3

Step-by-step explanation:

Volume formula will be:

where V - volume, k - coefficient of proportion, r² - squared radius, h - height

Substitute the known values to find the unknown:

Now find the volume of the taller can:

Correct option is A

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step-by-step explanation:

see explanation

step-by-step explanation:

a

(6r + 7) + (13 + 7r) ( remove brackets and collect like terms )

= 6r + 7 + 13 + 7r

= 13r + 20

b

remove brackets and collect like terms

13 - r - 1 + r

= 12 - r

c

remove brackets and collect like terms

= - 8 - r + 2r - 4

= - 12 + r

d

remove brackets and collect like terms

= 7r - - - 6r

[-   - = - - = - ]

= r -