What is the slope of a line perpendicular to the line whose equation is x-y=6x. Fully reduce your answer.

A linear equation is given to us and we need to find the slope of the line perpendicular to it . Given linear equation to us is ,

Let's convert this into Slope intercept form to find the slope of the line . The slope intercept form is y = mx + c , where m is the slope of the line.

Hencs on comparing to the standard form of Slope intercept form of the line , we get to know that the slope of the line is -5.

The equation of a perpendicular line to y = -5x

must have a slope that is the negative reciprocal of the original slope. Hence ,

b

step-by-step explanation:

the equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

calculate m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (0, 4) and (x₂, y₂ ) = (3, - 5) ← 2 points on the line

m = = = - 3

with m = - 3 and (a, b) = (3, - 5), then

y - (- 5) = - 3(x - 3), that is

y + 5 = - 3(x - 3) → b

the answer would be 44.79

plz mark brainliest

step-by-step explanation: