How do you find the average rate of change for f(x)=9-x^2 between two points: x=0 to x=3? Please I have a final tomorrow and I’m clueless

The average rate of change is -3.

Step-by-step explanation:

We are given the function:

And we want to find the average rate of change from x = 0 to x = 3.

In other words, we will compute the function at the two endpoints, and then find the slope of the line that crosses the two points.

For our first endpoint at x = 0, our function evaluates to:

So, our first point is (0, 9).

For our second endpoint at x = 3, our function evaluates to :

So, our second point is (3, 0).

Then by the slope formula, our average rate of change will be:

use the power rule  

( a b ) n = a n b n

to distribute the exponent.

apply the product rule to  

3 x 2 y 3 . ( 3 x 2 ) 2 ( y 3 ) 2

apply the product rule to  

3 x 2 . 3 2 ( x 2 ) 2 ( y 3 ) 2

raise  

3

to the power of  

2 . 9 ( x 2 ) 2 ( y 3 ) 2 multiply the exponents in   ( x 2 ) 2

.

apply the power rule and multiply exponents,  

( a m ) n = a m n . 9 x 2 ⋅ 2 ( y 3 ) 2

multiply  

2   by   2 . 9 x 4 ( y 3 ) 2

multiply the exponents in  

( y 3 ) 2 .

apply the power rule and multiply exponents,  

( a m ) n = a m n . 9 x 4 y 3

⋅

2

multiply  

3   by   2 . 9 x 4 y 6

step-by-step explanation:

3; 9 is 8 to -4

step-by-step explanation: