Write two different congruent statements that indicate the triangles in each pair are congruent ( ODD NUMBER QUESTIONS ONLY)

Step-by-step explanation:

13) QR ≅ BP   ;  RP ≅ PA ;  PQ ≅ AB

ΔQRP ≅ΔBPA        by Side Side Side Congruent

QR ≅ BP ; ∠R ≅ ∠BPA ;  RP  ≅ PA

ΔQRP ≅ ΔBPA            by Side Angle Side congruent

15) ML ≅ WV ; MX ≅ WX ;  LX ≅ VX;

ΔMLX ≅ ΔWVX    Side side side congruent

∠L ≅ ∠V   ;  ML ≅ WV ; ∠M ≅ ∠W

ΔMLX ≅ ΔWVX    Angle side Angle congruent

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!

25 questions , because they start with 100.  

350-100=250 .  

. 250/10=25

step-by-step explanation:

first take off 100, then what x 10 = 250? that is your answer. (25)