A bag contains 5 milk and 13 dark chocolates. A sweet is selected at random.
What is the probability of choosing:
P(milk)
=

P(not milk)
=

P(milk) 5/18 - 27% P(not milk) 13/18- 73%

Step-by-step explanation:

total chocolates in the bag= 18   (5 milk chocolates + 13 dark chocolates= 18 chocolates in total)

to find percentages divide numerator by denominator ( 5/18 = 27%) (13/18=73%)

P(milk) - 27% chance you will get milk chocolate

P(not milk) 73% chance you will get dark chocolate

It is more likey to get dark chocolate

honesty mood

step-by-step explanation:

the answer is y < -3 or   y > 3

-3y > 7 + 2

-3 y > 9

y < -3