10 snails is to be chosen from this population. Find the probability that the percentage of streaked-shelled snails in the sample will be (a) 50%. (b) 60%. (c) 70%.

Here is the full question:

(a) 0.2007

(b) 0.2510

(c) 0.2150

Step-by-step explanation:

Given that:

The sample size = 10

Sample proportion= 60% 0.6

Let X represents the no of streaked-shell snails.

The Probability mass function (X) is:

The Binomial probability with mean μ = np

= 10 * 0.6

= 6

Standard deviation σ =

=

= 1.55

The probability that the percentage of the streaked-shelled snails in the sample will be:

a)

= 0.2007

b)

= 0.2510

c)

= 0.2150

there are many solutions.

step-by-step explanation:

step 1: simplify both sides of the equation.

4x+6=4x^2+10x−4

step 2: subtract 4x^2+10x-4 from both sides.

4x+6−(4x^2+10x−4)=4x^2+10x−4−(4x^2+10x−4)

−4x^2−6x+10=0

step 3: factor left side of equation.

−2(2x+5)(x−1)=0

step 4: set factors equal to 0.

x=-5/2 or x=1