Which of the options is a solution for the following system of inequalities (2x+y>3 (x-y>1

(5,-2)
(0,5)
(0,0)
(0,-5)

(5, - 2)

Step-by-step explanation:

2x+y>3

x-y>1

2x + y > 3 - - - - (1)

x - y > 1 - - - (2)

Using trial and error method :

Using :

(5,-2)

2x + y > 3

2(5) + (-2) > 3

10 - 2 > 3

8 > 3 (true)

x - y > 1

5 - (-2) >1

5 + 2 > 1

7 > 1 (True)

For 0,5

2x + y > 3

2(0) + (5) > 3

0 + 5 > 3

5 > 3 (true)

x - y > 1

0 - (5) >1

-5 > 1

--5 > 1 (false)

Also, all other options do not hold true for bitb inequality statements, hence answer is (5, - 2)

the bolded word " farsighted" could be replaced with visionary.

answer: 75°

step-by-step explanation:

∠esk is the supplement of ∠edk, so is 100°. ∠esd = 1/2·arc ed, so is 25°.

since ∠esk = ∠esd + ∠dsk

you have 100° = 25° + ∠dsk . .

fill in known values 75° = ∠dsk . . . . .

subtract 25°

step-by-step explanation: