Given z1 =9+9/3i and z2 = 2+/3i, what is z2-z1? 8+7/3i

-7-8/3i

7+ 10/3i

-7+ 10/3i

z2 - z1 = 7/3i

Step-by-step explanation:

Given the following complex number:

z1 = 9+i/3i

z2 =  2+i/3i,

Taking the difference

z2 - z1 = 9+i/3i - (2+i))/3i)

z2-z1 = (9+i-(2+i))/31

z2 - z1 = 9+i -2-i/3i

z2-z1 = 9-2/3i

z2 - z1 = 7/3i

Note that the complex number given was not properly written and the ones used were assumed. Same procedure an be used for other complex numbers that might be given.

check the picture below.

i dont get the question

step-by-step explanation: