In triangle ABC, point A is located at (-9, -6), point B is located at (0,5), and point C is located at (6, 1). Find the distance from point A to the centroid of triangle ABC.
5
7.5
10
15

three-fourths of an hour

36÷48=0.75

0.75=

the answer is 489

step-by-step explanation:

"standard form:

3x2 + 14x − 10 = 0

solutions based on quadratic formula:

x1   = −14 − √ 142 − 4×3×(−10) /   2×3   = −14 − 2 × √ 79 /   6   ≈ −5.296

x2   = −14 + √ 142 − 4×3×(−10) /   2×3   = −14 + 2 × √ 79 /   6   ≈ 0.629