A newsstand seller sold a total of 68 magazines and newspapers, which brought in a total of $199 on a certain day. Suppose newspapers are sold at $2 per copy and magazines are sold at $5 per copy. How many magazines were sold on that day

21

Step-by-step explanation:

Using inequality to solve this question, we say

Let the total number of newspapers sold be x

Let the total number of magazines sold by y

x + y = 68

Suppose 1x = $2 and 1y = $5, then

2x + 5y = $199

Solving both as a simultaneous equation, we get that

2(68 - y) + 5y = $199

136 - 2y + 5y = $199

136 + 3y = $199

3y = 199 - 136

3y = 63

y = 63/3

y = 21

Then solving for x, we have

x + 21 = 68

x = 68 - 21

x = 47

Therefore, a total of 21 magazines were sold that day

d

step-by-step explanation:

given

y + 3 = - 4(x - 2) ← distribute the parenthesis

y + 3 = - 4x + 8 ( subtract 3 from both sides )

y = - 4x + 5 → d