A bag contains cards numbered from 1 to 14 one card is drawn at random find the probability of a.) Selecting a prime number of a multiple of four

b.) selecting a multiple of two or a multiple of three

One: P = 1/2 = 0.5

Two: P = 8/14 = 4/7 = 0.714

Step-by-step explanation:

One

I take it that the question is a prime number or 4.

P(four) = 1/14

The primes are 2,3,5,7,11,13. There are 6 of them

P(prime) = 6/14

P(prime or four) = 6/14 + 1/14 = 7/14 = 1/2

Two

Multiple of 2 := 2 4 6 8 10 12 14

Multiple of 3 :=  9 in addition to 6 and 12 which cannot be counted twice.

P(2 or 3) = 8/14 = 4/7 = 0.714

lol

step-by-step explanation:

the 1st digit is in the 100s n its 1

step-by-step explanation:

3,589÷18 = 199.389

so the first digit of the quotient is in the 100s n its 1