Question 5 (4 points) (06.01 MC)
Quadrilateral ABCD has coordinates A(3,-5), B (5, -2), C (10, -4), D (8, -7). Quadrilateral ABCD is a (4 points)
Oa
rectangle, because opposite sides are congruent and adjacent sides are perpendicular
square, because all four sides are congruent and adjacent sides are perpendicular
parallelogram, because opposite sides are congruent and adjacent sides are not perpendicular
rhombus, because all four sides are congruent and adjacent sides are not perpendicular
Ob
Od

It’s a parallelogram

Step-by-step explanation:

Explanation:

Given : A(3,−5),B(5

,

−

2

)

,

C

(

10

,

−

4

)

,

D

(

8

,

−

7

)

Slope

m

A

B

=

−

2

+

5

5

−

3

=

3

2

Slope

m

B

C

=

−

4

+

2

10

−

5

=

−

2

5

Slope

m

C

D

=

−

7

+

4

8

−

10

=

3

2

Slope

m

D

A

=

−

7

+

5

8

−

3

=

−

2

5

Slopes of opposite sides are equal. Hence, they are parallel.

−−→

A

B

=

s

r

t

(

(

5

−

3

)

2

+

(−2+5)2)=√13

−−→

B

C

=

s

r

t

(

(

5

−

10

)

2

+

(

−

2

+

4

)

2

)

=

√

29

−−→

C

D

=

s

r

t

(

(

8

−

10

)

2

+

(

−

7

+

4

)

2

)

=

√

13

−−→

D

A

=

s

r

t

(

(

8

−

3

)

2

+

(

−

7

+

5

)

2

)

=

√

29

Since only opposite sides are parallel and equal, and the product of the slopes of the adjacent sides not equal to (-1), it a simple parallel.

It's a square.

Step-by-step explanation:

I took the test.

x = -4

step-by-step explanation:

- 20 - 4(x + 3) = 4x

=> -20 - 4x - 12 = 4x

=> - 32 -4x = 4x

=> -32 = 4x + 4x

=> - 32 = 8x

=> -32/8 = x

=> -4 = x