Show that X^2-8x+20 can be written in the form (x-a)^2+a

x^2 + 8x + 20

a = 1

b = 8

c = 20

Discriminant = b^2 - 4ac

=> 8^2 - 4(1)(20)

=> 64 - 80

=> -16

As -16<0

So, equation has no real roots

I hope this will help you

(-:

Step-by-step explanation:

answer: it is 8

step-by-step explanation:

you know why its 8