An empty sand pit eeighs 6kg. The wight increases to 50kg when filled with sand. A different sand pit is 14% heavier but holds 22% less sand. Calculate the weight of this sand pit when it is full of sand

The weight of this sand pit when it is full of sand is 41.16kg

Step-by-step explanation:

For the first sand pit

It weighs 6kg and weight increases to 50kg when filled with sand.

Therefore, it can hold 50kg - 6kg = 44kg of sand

For the second sand pit

From the question, it is 14% heavier, that is, the weight will be

6kg + (14/100) × 6kg  = 6kg + 0.84kg

= 6.84kg

∴ The weight of the different sand pit is 6.84kg

Also from the question, it holds 22% less sand, that is, the weight of the sand it holds will be

44kg - (22/100) × 44kg = 44kg - 9.68kg

= 34.32kg

∴The weight of sand it holds is 34.32kg

The weight of this sand pit when it is full of sand is the sum of the weight of the sand pit and the weight pf sand it holds, that is,

Weight of sand pit = 6.84kg + 34.32kg = 41.16kg

Hence, the weight of this sand pit when it is full of sand is 41.16kg

15

step-by-step explanation:

we are given the following expression and we are to solve it and find the product:

-13 × (-5)

solving the given expression in the standard order of solving a mathematical expression, beginning with the opening of brackets and then multiplying the terms and changing their signs.

-3 × -5 = 15 (answer is positive because when negative is multiplied with negative, it gives a positive answer)

all the angles opposite to the angle 150 would be 150 and all the angles that are next to 150 are 30 because they equal 180 it you add it up.

step-by-step explanation: