At a certain school, 25% of the students wear a watch and 30% wear a braclet. 60% of the students wear neither a watch nor a braclet. (a) One of the students is chosen at random. What is the probability that this student is wearing a watch or a braclet

Complete question :

At a certain school, 25% of the students wear a watch and 30% wear a braclet. 60% of the students wear neither a watch nor a braclet. (a) One of the students is chosen at random. What is the probability that this student is wearing a watch or a braclet (b) What is the probability that this student is wearing both a watch and a bracelet?

0.40 ; 0.15

Step-by-step explanation:

Given :

w = watch

b = bracelet

P(w) = 0.25

P(b) = 0.3

P(w' U b') = 0.60

Probability that student is wearing a watch or a bracelet :

P(w U b) = 1 - P(w' U b')

P(w U b) = 1 - 0.60

P(w U b) = 0.4

Probability that student is wearing a watch and a bracelet :

P(w n b) = p(w) + p(b) - p(w U b)

P(w n b) = 0.25 + 0.3 - 0.4

P(w n b) = 0.55 - 0.4

P(w n b) = 0.15

i think c. but don't trust it.

step-by-step explanation: