Ту 12
What is the equation of the line that is parallel to the
given line and passes through the point (12,-2)?
10
8
(12,6)
x + 10
6.
vx
4
2
O y=x+
O y = -x + 12
O y=-3x - 10
O y = x - 12
-10 -3 -6 -4 -2 24 6 8 10 12 14 X
(12-2)
(0,4)
46
8
-10
w12
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