If 18.5 grams of CuCl2 react with 22.8 grams of NaNO3, what mass of NaCl can be formed? CuCl2 + NaNO3 → Cu(NO3)2 + NaCl 12.4 g NaCl 15.7 g NaCl 16.2 g NaCl 28.4 g NaCl

15.7 g

Step-by-step explanation:

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