Find three consecutive integers such that the square of the first, increased by the last, is 32.

Step-by-step explanation:

In order to find the 3 consecutive digits here, we need to note that consecutive numbers are numbers that appear as the number right above each other.

For example: 2, 3, 4 are consecutive, as are -10, -9, -8.

We can assign the first term a variable, let's do x. Since we know the next two terms are consecutive, we can define them with and .

We also know that the first number squared, increased by the last, is 32. This can be modeled by the equation

Let's solve for x in that equation by using the XBOX Method in quadratics.

Now that we know two values of x that might work, we need to plug them into our equation to test if they actually do work.

5

-6

We can see here that -6 won't work as it doesn't satisfy our equation. However, 5 does work. That means our first number is 5, making our next two numbers 6 and 7.

Hence - 5, 6, 7.

Hope this helped!

b

step-by-step explanation:

given

- 2 (3x + 12y - 5 - 17x - 16y + 4 )

simplify the parenthesis by collecting like terms

= - 2 (- 14x - 4y - 1) ← distribute the parenthesis by - 2

= 28x + 8y + 2 → b