PLEASE HELPPP I WILL ANME BRAINLIEST Find \tan(\beta)tan(β)tangent, left parenthesis, beta, right parenthesis in the triangle. Choose 1
Choose 1

(Choice A)
A
\dfrac{3}{5}
5
3

start fraction, 3, divided by, 5, end fraction

(Choice B)
B
\dfrac{4}{5}
5
4

start fraction, 4, divided by, 5, end fraction

(Choice C)
C
\dfrac{3}{4}
4
3

start fraction, 3, divided by, 4, end fraction

(Choice D)
D
\dfrac{4}{3}
3
4

start fraction, 4, divided by, 3, end fraction

hi there!

first we need to find out how much they are adding to each number to make the next number.

ex: 4 + 4 = 8, 8 + 8 = 16, and so on.

so continuing with 32,

32 + 32 = 64

64 + 64 = 128

128 + 128 = 256

256 + 256 = 512

4, 8, 16, 32, 64, 128, 256, 512

the 8th term of the sequence will be 512

hope this ! ~

“a term can be a signed number, a variable, or a constant multiplied by a + sign or j sign. in , the terms are 5x , 3y and 8. when a term is made up of a constant multiplied by a variable or variables, that constant is called a coefficient.” i hope this you.

x:       y:  

-1         4

0         4

1         6

2         18

3         20